document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=953581>Question 953581</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the 4th term of an arithmetic sequence is 3 and the 20th term is 35, find the 100th term of the sequence. \r<BR>\n" );
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document.write( "I believe the equation = -5 + 2n \r<BR>\n" );
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document.write( "and maybe the 100th number is 95\r<BR>\n" );
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document.write( "It does not make senses to me. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582373 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582373\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An arithmetic sequence uses the following formula for the nth tern<BR>\n" );
document.write( "Xn = a +(d*(n-1)), where Xn is the nth term, a is the first term, n is number of the term in the sequence, we are given<BR>\n" );
document.write( "3 = a +(d*(4-1)) = a + 3d<BR>\n" );
document.write( "35 = a +(d*(20-1)) = a +19d<BR>\n" );
document.write( "using the first equation solve for a<BR>\n" );
document.write( "a = 3-3d<BR>\n" );
document.write( "substitute for a in second equation<BR>\n" );
document.write( "35 = 3-3d +19d<BR>\n" );
document.write( "16d = 32<BR>\n" );
document.write( "d = 2 and a = 3 - 6 = -3<BR>\n" );
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document.write( "our equation for the nth term is<BR>\n" );
document.write( "Xn = -3 +(2*(n-1))<BR>\n" );
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document.write( "now for the 100th term<BR>\n" );
document.write( "X100 = -3 +(2*(100-1)) = 195\r<BR>\n" );
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