document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=953400>Question 953400</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimter of a rectangale is 54cm the length is 3 less than twice the width find the length and the width what is the anwser<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582355 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582355\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=width; Length=L=2W-3; Perimeter=P=2(L+W)<BR>\n" );
document.write( "P=2(L+W) Substitute for L<BR>\n" );
document.write( "54cm=2((2W-3)+W) Divide each side by 2.<BR>\n" );
document.write( "27cm=3W-3 Add 3 to each side.<BR>\n" );
document.write( "30cm=3W Divide each side by 3.<BR>\n" );
document.write( "10cm=W ANSWER 1: The width is 10cm.<BR>\n" );
document.write( "L=2W-3=2(10cm)-3=20cm-3=17cm ANSWER 2: The length is 17 cm.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "54cm=2(17cm+10cm)<BR>\n" );
document.write( "54cm=2(27cm)<BR>\n" );
document.write( "54cm=54cm<BR>\n" );
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