document.write( "Question 953542: The function f is a fifth-degree polynomial with
\n" ); document.write( "the x-intercepts -4, 1, and 7,
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\n" ); document.write( "\n" ); document.write( "I know it would have to have (x+4)(x-1)(x+7) and possibly either squared or cubics for exponents but I am confused about how I would insert the 112 and the f (x) ≥ 0 for x ≤ 7. I don't understand what those last two are asking me to do to make it true.\r
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Algebra.Com's Answer #582350 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The function f is a fifth-degree polynomial with
\n" ); document.write( "the x-intercepts -4, 1, and 7,
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\n" ); document.write( "We have the three factors (x+4)(x-1)(x-7), the y intercept 4 * 1 * 7 = 28 not 112.
\n" ); document.write( "28 goes into 112 4 times so lets change the factors to (x+4)(x-1)(4x-28)
\n" ); document.write( "4x + 28 = 0; x still equal -7
\n" ); document.write( "but now we can construct the equation
\n" ); document.write( "FOIL(x+4)(x-1) = x^2 + 3x - 4
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\n" ); document.write( "x^2 + 3x - 4
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\n" ); document.write( "4x^3 - 16x^2 - 100x + 112 but this only a third degree equation but satisfies the requirements
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\n" ); document.write( "Green line is y=112
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