document.write( "Question 953542: The function f is a fifth-degree polynomial with
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document.write( "the x-intercepts -4, 1, and 7,
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document.write( "y-intercept 112 and
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document.write( "f (x) ≥ 0 for x ≤ 7\r
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document.write( "I know it would have to have (x+4)(x-1)(x+7) and possibly either squared or cubics for exponents but I am confused about how I would insert the 112 and the f (x) ≥ 0 for x ≤ 7. I don't understand what those last two are asking me to do to make it true.\r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #582350 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! The function f is a fifth-degree polynomial with \n" ); document.write( "the x-intercepts -4, 1, and 7, \n" ); document.write( "y-intercept 112 and \n" ); document.write( "f (x) ≥ 0 for x ≤ 7 \n" ); document.write( ": \n" ); document.write( "We have the three factors (x+4)(x-1)(x-7), the y intercept 4 * 1 * 7 = 28 not 112. \n" ); document.write( "28 goes into 112 4 times so lets change the factors to (x+4)(x-1)(4x-28) \n" ); document.write( "4x + 28 = 0; x still equal -7 \n" ); document.write( "but now we can construct the equation \n" ); document.write( "FOIL(x+4)(x-1) = x^2 + 3x - 4 \n" ); document.write( ": \n" ); document.write( "x^2 + 3x - 4 \n" ); document.write( " X (4x - 28) \n" ); document.write( "------------- \n" ); document.write( "4x^3 - 16x^2 - 100x + 112 but this only a third degree equation but satisfies the requirements \n" ); document.write( " \n" ); document.write( "Green line is y=112 \n" ); document.write( " |