document.write( "Question 953533: Pre-Algebra: Find the three solutions to the equation below.\r
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document.write( "2x - 4y = 4\r
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document.write( " a. (3,0) (4,0 (-4,0)\r
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document.write( " b. (2,0) (8,4) (-2,1)\r
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document.write( " c. (0,-1) (2,0) (1,-1/2)
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Algebra.Com's Answer #582320 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Let's go through the choices\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Choice A) (3,0) (4,0) (-4,0) \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the first point of choice A is (3,0) which means x = 3 and y = 0. They BOTH need to make the equation true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x - 4y = 4 \n" ); document.write( "2(3) - 4(0) = 4 ... plug in (x,y) = (3,0) \n" ); document.write( "6 - 0 = 4 \n" ); document.write( "6 = 4 ... this is false, so (3,0) is NOT a solution making choice A NOT an answer. We move on to the next choice\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Choice B) (2,0) (8,4) (-2,1) \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Checking (2,0)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x - 4y = 4 \n" ); document.write( "2(2) - 4(0) = 4 \n" ); document.write( "4 - 0 = 4 \n" ); document.write( "4 = 4 ... looks good\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Checking (8,4)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x - 4y = 4 \n" ); document.write( "2(8) - 4(4) = 4 \n" ); document.write( "16 - 16 = 4 \n" ); document.write( "0 = 4 ... false, so we eliminate choice B\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----------------------------------------------------------------\r \n" ); document.write( "\n" ); document.write( "Choice C) (0,-1) (2,0) (1,-1/2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Checking (0,-1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x - 4y = 4 \n" ); document.write( "2(0) - 4(-1) = 4 \n" ); document.write( "0 + 4 = 4 \n" ); document.write( "4 = 4 ... looks good\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Checking (2,0)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x - 4y = 4 \n" ); document.write( "2(2) - 4(0) = 4 \n" ); document.write( "4 - 0 = 4 \n" ); document.write( "4 = 4 ... looks good\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Checking (1, -1/2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x - 4y = 4 \n" ); document.write( "2(1) - 4(-1/2) = 4 \n" ); document.write( "2 + 2 = 4 \n" ); document.write( "4 = 4 ... looks good\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==========================================================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So in the end, choice C is the answer since ALL of the points listed in choice C make the equation true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------------------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you need more one-on-one help, email me at jim_thompson5910@hotmail.com. You can ask me a few more questions for free, but afterwards, I would charge you ($2 a problem to have steps shown or $1 a problem for answer only).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Alternatively, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Any amount is greatly appreciated as it helps me a lot. This donation is to support free tutoring. Thank you.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jim\r \n" ); document.write( "\n" ); document.write( "------------------------------------------------------------------------------------------------------------------------ \n" ); document.write( " |