document.write( "Question 953481: What are the foci of the ellipse? Graph the ellipse.\r
\n" ); document.write( "\n" ); document.write( "x^2/49+y^2/64=1\r
\n" ); document.write( "\n" ); document.write( "Foci (0,+-sqrt 15)
\n" ); document.write( "Foci (0,+-sqrt 113)
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Algebra.Com's Answer #582288 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F49%2By%5E2%2F64=1\"\r
\n" ); document.write( "\n" ); document.write( "\"a%5E2=49\"=>\"a=7\"\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2=64\"=>\"b=8\"\r
\n" ); document.write( "\n" ); document.write( "The formula generally associated with the focus of an ellipse is \"b%5E2=+a%5E2+%26%238722%3B+c%5E2\" where \"c\" is the distance from the focus to vertex.\r
\n" ); document.write( "\n" ); document.write( "\"b%5E2=+a%5E2+%26%238722%3B+c%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"64=+49+%26%238722%3B+c%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2=++64-49\"\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2=++15\"\r
\n" ); document.write( "\n" ); document.write( "\"c=+sqrt%28+15%29\" or \"c=-+sqrt%28+15%29\"\r
\n" ); document.write( "\n" ); document.write( "so, answer is: Foci (0,+-sqrt 15)\r
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