document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=953487>Question 953487</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Richard is 5 years older then Sheila. Four times Shiela's age increased by 3 years equals thee times Richards age diminished by 2 years. Find Richards age.\r<BR>\n" );
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document.write( "Please explain the steps to get to this answer too\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582286 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582286\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> R = S+5<BR>\n" );
document.write( "4S+3 = 3R-2 and since we just said that R= S+5:<BR>\n" );
document.write( "4S+3 = 3(S+5)- 2 Let's multiply on the right to clear the parenthesis:<BR>\n" );
document.write( "4S+3 = 3S+15-2 Subtract on the right:<BR>\n" );
document.write( "4S+3 = 3S+13 Now subtract 3S on both sides, and also subtract 3 on both sides<BR>\n" );
document.write( "S = 10 Sheila is 10 years old. And Richard? Well, the problem says he's 5 years older than Sheila, so Richard is 15.\r<BR>\n" );
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document.write( "Proof: <BR>\n" );
document.write( "4S+3 = 3R-2<BR>\n" );
document.write( "4(10)+3 = 3(15)-2<BR>\n" );
document.write( "43 = 43 We got the right answer. </SPAN>\n" );
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