document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=953452>Question 953452</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the lengh of a rectangle is 10 feet longer than the with. if the perimeter is 96 feet find the lengh and the with of the perimeter </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582237 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582237\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> So you say that:<BR>\n" );
document.write( "L = W+10<BR>\n" );
document.write( "The perimeter is:<BR>\n" );
document.write( "2L + 2W = 96 And since we just said that L = W+10, let's substitute like this:<BR>\n" );
document.write( "2(W+10) + 2W = 96 Multiply of the left:<BR>\n" );
document.write( "2W + 20 + 2W = 96 Add W's on left and subtract 20 on both sides:<BR>\n" );
document.write( "4W = 76 Divide both sides by 4:<BR>\n" );
document.write( "W = 19 <-- This is the Width. And we said the length is 10 more:<BR>\n" );
document.write( "L = 19+10 = 29<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "2L + 2W = 96; 2(29) + 2(19) = 96; 58 + 38 = 96; 96 = 96 We've got the right answer. </SPAN>\n" );
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