document.write( "Question 81245: can someone check this for me?
\n" ); document.write( "I have to factor completely.\r
\n" ); document.write( "\n" ); document.write( "x^2+9x+18
\n" ); document.write( "18+9x+x^2=0
\n" ); document.write( "(6+x)(3+x)=0
\n" ); document.write( "6+x=0
\n" ); document.write( "6+-6+x=0+-6
\n" ); document.write( "0+x=0+-6
\n" ); document.write( "x=0+-6
\n" ); document.write( "x=-6
\n" ); document.write( "

Algebra.Com's Answer #58222 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You're on the right track. You just need to solve for the other value of x\r
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\n" ); document.write( "\n" ); document.write( "Set \"3%2Bx\" equal to zero\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%2Bx=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=-3\" Subtract 3 from both sides\r
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\n" ); document.write( "\n" ); document.write( "So the solution is (adding to what you have)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=-6\" or \"x=-3\"
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