document.write( "Question 953354: If C is the event that a student will stay home to study and D is the event that she will instead go to a movie, P(C) = 0.70, and P(D) = 0.25, find (a) P(C'); (b) P(C or D). \n" ); document.write( "
Algebra.Com's Answer #582176 by Theo(13342)\"\" \"About 
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p(c) = .7
\n" ); document.write( "p(d) = .25\r
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\n" ); document.write( "\n" ); document.write( "these events are mutually exclusive since she can't stay at home and study and go out to see a movie at the same time.\r
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\n" ); document.write( "\n" ); document.write( "p(c and d) is therefore equal to 0.\r
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\n" ); document.write( "\n" ); document.write( "p(c or d) = p(c) + p(d) - p(c and d) = .7 + .25 - 0 = .95.\r
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\n" ); document.write( "\n" ); document.write( "p(c') is the probability that she won't stay home and study.\r
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\n" ); document.write( "\n" ); document.write( "p(c') is equal to 1 - p(c) which is equal to 1 - .7 which is equal to .3\r
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\n" ); document.write( "\n" ); document.write( "since all the probabilities added together must be equal to 1, she has:\r
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\n" ); document.write( "\n" ); document.write( "p(c) = .7
\n" ); document.write( "p(d) = .25
\n" ); document.write( "p(c or d) = .95\r
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\n" ); document.write( "\n" ); document.write( "p(c') = 1 - .7 = .3
\n" ); document.write( "p(d') = 1 - .25 = .75
\n" ); document.write( "p(c or d)' = 1 - .95 = .05\r
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\n" ); document.write( "\n" ); document.write( "p(c or d)' means the probability that she will not stay home and study and she will not go out to a movies. in other words, she'll do something else.\r
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\n" ); document.write( "\n" ); document.write( "the solution to your problem is:\r
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\n" ); document.write( "\n" ); document.write( "p(c') = .3 and p(c or d) = .95.\r
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