document.write( "Question 953334: Is it possible to get a negative z-zore?
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document.write( "the Philadelphia zoo reports that the mean life span of a Galápagos tortoise is 100 years. Assume that their life span follows a normal distribution with the mean= 100 years and standard deviation = 15 years.
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document.write( "a) find the probability that a randomly chosen tortoise will live longer than 70 years. \r
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document.write( "z= 70-100
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document.write( " --------- = -2
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document.write( " 15 \r
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document.write( "P(z> -2) 1-0.0228= 0.9772. that's the answer i got but i'm not sure if i did it correctly. \n" );
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Algebra.Com's Answer #582173 by Theo(13342)![]() ![]() You can put this solution on YOUR website! yes, it's possible to get a negative z-score.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if your actual score is less than the mean, you will get a negative z-score.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if your actual score is more than the mean, you will get a positive z-score.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you actual score is the same as the mean, you will get a z-score of zero.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your question is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the Philadelphia zoo reports that the mean life span of a Galápagos tortoise is 100 years. Assume that their life span follows a normal distribution with the mean = 100 years and standard deviation = 15 years.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a) find the probability that a randomly chosen tortoise will live longer than 70 years. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula for z-score is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z = (x-m)/s\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z is the z-score. \n" ); document.write( "x is the raw score \n" ); document.write( "m is the mean of the raw score \n" ); document.write( "s is the standard deviation of the raw score.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z = (70 - 100) / 15 which results in:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z = -2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you're looking for the probability for having a z-score of -2 or greater.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the z-score of -2 tells you that 2.28% of the area under the normal distribution curve is to the left of that z-score.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this means that 1 - .0228 = .9772 = 97.72% of the area under the normal distribution curve is to the right of that x-score.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this means that the probability that a turtle will live longer than 70 years is equal to 97.72%.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you did good. \n" ); document.write( " \n" ); document.write( " |