document.write( "Question 953313: Six less than the product of two consecutive positive integers is equal to six times their sum. Find the two integers. \n" ); document.write( "
Algebra.Com's Answer #582160 by macston(5194)\"\" \"About 
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n=first number; n+1=second number
\n" ); document.write( "((n)(n+1))-6=6(n+n+1)
\n" ); document.write( "n^2+n-6=6(2n+1)
\n" ); document.write( "n^2+n-6=12n+6 Subtract (12n+6) from each side.
\n" ); document.write( "n^2-11n-12=0\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"an%5E2%2Bbn%2Bc=0\" (in our case \"1n%5E2%2B-11n%2B-12+=+0\") has the following solutons:
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\n" ); document.write( " \"n%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-11%29%5E2-4%2A1%2A-12=169\".
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\n" ); document.write( " Discriminant d=169 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--11%2B-sqrt%28+169+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"n%5B1%5D+=+%28-%28-11%29%2Bsqrt%28+169+%29%29%2F2%5C1+=+12\"
\n" ); document.write( " \"n%5B2%5D+=+%28-%28-11%29-sqrt%28+169+%29%29%2F2%5C1+=+-1\"
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\n" ); document.write( " Quadratic expression \"1n%5E2%2B-11n%2B-12\" can be factored:
\n" ); document.write( " \"1n%5E2%2B-11n%2B-12+=+1%28n-12%29%2A%28n--1%29\"
\n" ); document.write( " Again, the answer is: 12, -1.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-11%2Ax%2B-12+%29\"

\n" ); document.write( "\n" ); document.write( "ANSWER 1: The first positive integer is 12.
\n" ); document.write( "x+1=12+1=13 ANSWER 2: The second positive integer is 13.
\n" ); document.write( "CHECK:
\n" ); document.write( "(12*13)-6=6(12+13)
\n" ); document.write( "156-6=6(25)
\n" ); document.write( "150=150
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