document.write( "Question 953313: Six less than the product of two consecutive positive integers is equal to six times their sum. Find the two integers. \n" ); document.write( "
Algebra.Com's Answer #582160 by macston(5194)![]() ![]() You can put this solution on YOUR website! n=first number; n+1=second number \n" ); document.write( "((n)(n+1))-6=6(n+n+1) \n" ); document.write( "n^2+n-6=6(2n+1) \n" ); document.write( "n^2+n-6=12n+6 Subtract (12n+6) from each side. \n" ); document.write( "n^2-11n-12=0
\n" ); document.write( "\n" ); document.write( "ANSWER 1: The first positive integer is 12. \n" ); document.write( "x+1=12+1=13 ANSWER 2: The second positive integer is 13. \n" ); document.write( "CHECK: \n" ); document.write( "(12*13)-6=6(12+13) \n" ); document.write( "156-6=6(25) \n" ); document.write( "150=150 \n" ); document.write( " \n" ); document.write( " |