document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=953274>Question 953274</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has a perimeter of 68 units and 2 lengths of 12 units. Find the width.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582131 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582131\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=perimeter; L=length; W=width<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "68 units=2(12 units+W) Divide each side by 2.<BR>\n" );
document.write( "34 units=12 units+W Subtract 12 units from each side.<BR>\n" );
document.write( "22 units=W ANSWER: The width of the rectangle is 22 units.<BR>\n" );
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document.write( "P=2(L+W)<BR>\n" );
document.write( "68 units=2(12 units + 22 units)<BR>\n" );
document.write( "68 units=2(24 units)<BR>\n" );
document.write( "68 units=68 units\r<BR>\n" );
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