document.write( "Question 953254: Mr Taylor has $10,000 to invest. he invested part of it at 8% and part of it at 6%. If his total simple interest was $760, find how much he invested for 1 year at each rate \n" ); document.write( "
Algebra.Com's Answer #582125 by macston(5194)![]() ![]() You can put this solution on YOUR website! Mr Taylor has $10,000 to invest. he invested part of it at 8% and part of it at 6%. If his total simple interest was $760, find how much he invested for 1 year at each rate \n" ); document.write( "E=8% investment; S=6% investment \n" ); document.write( "E+S=$10000 \n" ); document.write( "E=$10000-S \n" ); document.write( "0.08E+0.06S=$760 Substitute for E. \n" ); document.write( "0.08($10000-S)+0.06S=$760 \n" ); document.write( "$800-0.08S+0.06S=$760 Subtract $760 from each side. \n" ); document.write( "$40-0.02S=0 Add 0.02S to each side. \n" ); document.write( "$40=0.02S Divide each side by 0.02 \n" ); document.write( "$2000=S ANSWER 1: He invested $2000 at 6%. \n" ); document.write( "E=$10000-S=$1000-$2000=$8000 ANSWER 2: He invested $8000 at 8%. \n" ); document.write( "CHECK: \n" ); document.write( "0.08($8000)+0.06($2000)=$760 \n" ); document.write( "$640+$120=$760 \n" ); document.write( "$760=$760 \n" ); document.write( " |