document.write( "Question 953158: From a class of 6 male and 8 female students, a committee of 4 students is chosen. How many different committees contain more than 2 female students?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I thought of doing C (6,1) * C(8,3), but not sure if it makes sense.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #582107 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
From a class of 6 male and 8 female students, a committee of 4 students is chosen. How many different committees contain more than 2 female students?
\n" ); document.write( "
\r\n" );
document.write( "That's part of the answer, the number when the committee consiste of 1 male \r\n" );
document.write( "and 3 females, but there is a second case!  That is when the committee consists \r\n" );
document.write( "of all females and no males.\r\n" );
document.write( "\r\n" );
document.write( "Case 1.  Committees with exactly 3 females and 1 male.\r\n" );
document.write( "         (8 females choose 3)*(6 males choose 1) = (8C3)(6C1) = (56)(6) = 336.\r\n" );
document.write( "Case 2.  Committees with exactly 4 females and no males.\r\n" );
document.write( "         (8 females choose 4)= (8C4)= 70.\r\n" );
document.write( "\r\n" );
document.write( "Grand total: 336+70 = 406 ways.\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );