document.write( "Question 953226: Hi there! I am not very good at math and I have been stuck on this question for 20 minutes now. The question is: calculate the volume of a box to hold a sphere-shaped beaker with a volume of 413cm^3. The second part is : how much space is being occupied by the beaker and how much is being wasted, in percents.
\n" ); document.write( "Thank you so much, I honestly have no idea what to do.
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Algebra.Com's Answer #582106 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The volume of a sphere is:
\n" ); document.write( "\"+V%5Bs%5D+=+%284%2F3%29%2Api%2Ar%5E3+\"
\n" ); document.write( "where \"+r+\" is the radius
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\n" ); document.write( "You are given that:
\n" ); document.write( "\"+V%5Bs%5D+=+413+\" cm3
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\n" ); document.write( "\"+413+=+%284%2F3%29%2Ar%5E3+\"
\n" ); document.write( "Multiply both sides by \"+3+\"
\n" ); document.write( "\"+1239+=+4%2Api%2Ar%5E3+\"
\n" ); document.write( "Divide both sides by \"+4%2Api+\"
\n" ); document.write( "\"+309.75+%2F+pi+=+r%5E3+\"
\n" ); document.write( "\"+r%5E3+=+98.5966+\"
\n" ); document.write( "\"+r+=+4.6198+\"
\n" ); document.write( "---------------
\n" ); document.write( "check:
\n" ); document.write( "\"+V%5Bs%5D+=+%284%2F3%29%2Api%2Ar%5E3+\"
\n" ); document.write( "\"+V%5Bs%5D+=+%284%2F3%29%2Api%2A4.6198%5E3+\"
\n" ); document.write( "\"+V%28s%29+=+1.333%2A3.14159%2A98.5983+\"
\n" ); document.write( "\"+V%28s%29+=+412.997+\"
\n" ); document.write( "This looks close enough
\n" ); document.write( "-----------------------
\n" ); document.write( "If this sphere is tightly enclosed in a cube,
\n" ); document.write( "the volume of the box is \"+V%5Bc%5D+=++%282r%29%5E3+\"
\n" ); document.write( "This is because \"+2r+\" is equal to a side
\n" ); document.write( "of the box
\n" ); document.write( "-----------------
\n" ); document.write( "\"+V%5Bc%5D+=+%28+2%2A4.6198+%29%5E3+\"
\n" ); document.write( "\"+V%5Bc%5D+=+9.2396%5E3+\"
\n" ); document.write( "\"+V%5Bc%5D+=+788.7866+\"
\n" ); document.write( "----------------------
\n" ); document.write( "\"+V%5Bc%5D+-+V%5Bs%5D+=+788.7866+-+413+\"
\n" ); document.write( "\"+V%5Bc%5D+-+V%5Bs%5D+=+375.7866+\" ( wasted volume in cm3 )
\n" ); document.write( "-------------------------
\n" ); document.write( "You are asked for:
\n" ); document.write( "\"+%28+V%5Bc%5D+-+V%5Bs%5D+%29+%2F+V%5Bc%5D+%29%2A100+\" which is a %
\n" ); document.write( "\"+%28+375.7866+%2F+788.7866+%29%2A100+\"
\n" ); document.write( "\"+.4764%2A100+=+47.64+\"
\n" ); document.write( "47.64% is wasted space inside the cube
\n" ); document.write( "----------------
\n" ); document.write( "Hope I got it -tough calculations\r
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