document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=953256>Question 953256</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of Bob, Mary and Sue's ages is fifty nine. Bob is twice Sue's age. Mary is one year younger than Sue. Find the age of each person. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582105 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582105\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> S=Sue's age; B=bob's age=2S; M=Mary's age=S-1yr; <BR>\n" );
document.write( "B+M+S=59yrs Substitute for B and S<BR>\n" );
document.write( "2S+S-1yr+S=59yrs Add 1 yr to each side.<BR>\n" );
document.write( "4S=60yrs Divide each side by 4<BR>\n" );
document.write( "S=15 years ANSWER 1: Sue is 15 years old.<BR>\n" );
document.write( "B=2S=2(15yrs)=30 yrs ANSWER 2: Bob is 30 years old.<BR>\n" );
document.write( "M=S-1 yr=15 yrds-1yr=14 years ANSWEr 3: Mary is 14 years old.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "B+M+S=59yrs<BR>\n" );
document.write( "30yrs+14yrs+15yrs=59yrs<BR>\n" );
document.write( "59yrs=59yrs<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );