document.write( "Question 953175: 3x-4;4x-2 and 7x-6 form an arithmetic sequence. Determine x and hence the three terms \n" ); document.write( "
Algebra.Com's Answer #582071 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "If a sequence of values follows a pattern of adding a fixed amount from one term to the next, it is referred to as an arithmetic sequence. The number added to each term is constant (always the same).\r
\n" ); document.write( "\n" ); document.write( "The fixed amount is called the common difference, \"d\", referring to the fact that the difference between two successive terms yields the constant value that was added.
\n" ); document.write( "To find the common difference, subtract the first term from the second term.\r
\n" ); document.write( "\n" ); document.write( "\"d=4x-2+-%283x-4%29\"\r
\n" ); document.write( "\n" ); document.write( "\"d=4x-2+-3x%2B4\"\r
\n" ); document.write( "\n" ); document.write( "\"d=x%2B2\"\r
\n" ); document.write( "\n" ); document.write( "To find any term of an arithmetic sequence:
\n" ); document.write( "\"a%5Bn%5D=a%5B1%5D%2B%28n-1%29d\"
\n" ); document.write( "where \"a%5B1%5D\" is the first term of the sequence, \"d\" is the common difference,\"+n\" is the number of the term to find\r
\n" ); document.write( "\n" ); document.write( "since we have three terms \"3x-4\", \"4x-2\", \"7x-6\", and common difference \"d=x%2B2\", substitute it in formula above:\r
\n" ); document.write( "\n" ); document.write( "\"a%5Bn%5D=a%5B1%5D%2B%28n-1%29d\"\r
\n" ); document.write( "\n" ); document.write( "\"7x-6=3x-4%2B%283-1%29%28x%2B2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"7x-6=3x-4%2B2%28x%2B2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"7x-6=3x-4%2B2x%2B4\"\r
\n" ); document.write( "\n" ); document.write( "\"7x-6=5x\"\r
\n" ); document.write( "\n" ); document.write( "\"7x-5x=6\"\r
\n" ); document.write( "\n" ); document.write( "\"2x=6\"\r
\n" ); document.write( "\n" ); document.write( "\"x=3\"\r
\n" ); document.write( "\n" ); document.write( "so, your sequence is:\r
\n" ); document.write( "\n" ); document.write( "\"3%2A3-4\"=>\"5\"
\n" ); document.write( "\"4%2A3-2\"=>\"10\"
\n" ); document.write( "\"7%2A3-6\"=>\"15\"\r
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