document.write( "Question 953132: If I have $12 in nickels and dimes and have 3 time as many nickels as dimes, how many dimes do I have? Also how to work it. \n" ); document.write( "
Algebra.Com's Answer #582054 by macston(5194)\"\" \"About 
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d=dimes; n=nickels=3d
\n" ); document.write( "$0.10d+$0.05n=$12 (multiply number of coins by value of coins to get amount)Substitute for n.
\n" ); document.write( "$0.10d+$0.05(3d)=$12
\n" ); document.write( "$0.10d+$0.15d=$12
\n" ); document.write( "$0.25d=$12 Divide each side by $0.25.
\n" ); document.write( "d=48 ANSWER: There were 48 dimes.
\n" ); document.write( "3d=3(48)=144 There were 144 nickels.
\n" ); document.write( "CHECK:
\n" ); document.write( "$0.10(48)+$0.05(144)=$12
\n" ); document.write( "$4.80+$7.20=$12
\n" ); document.write( "$12=$12
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