document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=953073>Question 953073</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter fence of a rectangular community park is 310cm. Its length is 10m less than twice its width. Find the dimensions of the park </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582014 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582014\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> NOTE: I changed the perimeter from 310 cm to 310 m.<BR>\n" );
document.write( "W=width; L=length=2W-10m; P=perimeter=2(L+W)=310m<BR>\n" );
document.write( "P=2(L+W) Divide each side by 2.<BR>\n" );
document.write( "310m/2=L+W Substitute for L.<BR>\n" );
document.write( "155m=2W-10m+W  Add 10m to each side.<BR>\n" );
document.write( "165m=3W Divide each side by 3.<BR>\n" );
document.write( "55m=W ANSWER 1: The width is 55 meters.<BR>\n" );
document.write( "L=2W-10m=2(55m)-10m=100m ANSWER 2: The length is 100 m.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "310 m=2(100m+55M)<BR>\n" );
document.write( "310m=2(155m)<BR>\n" );
document.write( "310m=310m<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );