document.write( "Question 953045: Can someone please assist me in setting this equation up and explain why I am doing it in such a way... please?
\n" ); document.write( "A lake is stocked with a certain species of fish, the fish population is modeled by the function p=700/e^-0.8t
\n" ); document.write( "where P is the number of fish in thousands and t is measured in years since the lake was stocked
\n" ); document.write( "Find the fish population after 2 years?\r
\n" ); document.write( "\n" ); document.write( "After how many years will the fish population be 250000 fish?
\n" ); document.write( "THanks!
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Algebra.Com's Answer #582004 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A lake is stocked with a certain species of fish,
\n" ); document.write( " the fish population is modeled by the function \"p=700%2F%28e%5E%28-0.8t%29%29\"
\n" ); document.write( " where P is the number of fish in thousands
\n" ); document.write( " and t is measured in years since the lake was stocked
\n" ); document.write( ":
\n" ); document.write( "Find the fish population after 2 years?
\n" ); document.write( "t = 2,so we have
\n" ); document.write( "\"p=700%2F%28e%5E%28%28-0.8%2A2%29%29%29\"
\n" ); document.write( "\"p=700%2F%28e%5E%28-1.6%29%29\"
\n" ); document.write( "find e^-1.6 on your calc
\n" ); document.write( "\"p=700%2F.2019\"
\n" ); document.write( "p = 3,467 fish after 2 yrs
\n" ); document.write( ":
\n" ); document.write( "After how many years will the fish population be 250000 fish?
\n" ); document.write( "Write this as
\n" ); document.write( "250000 = \"700%2F%28e%5E%28-.8t%29%29\"
\n" ); document.write( "multiply both sides by e^(-.8t)
\n" ); document.write( "\"250000%2Ae%5E%28-.8t%29+=+700\"
\n" ); document.write( "divide both sides by 250000
\n" ); document.write( "\"e%5E%28-.8t%29+=+700%2F250000\"
\n" ); document.write( "\"e%5E%28-.8t%29+=+.0028\"
\n" ); document.write( "find the nat log of both sides
\n" ); document.write( "\"ln%28e%5E%28-.8t%29%29+=+ln%28.0028%29\"
\n" ); document.write( "the log equiv of exponents, find the ln of .0028
\n" ); document.write( "-.8t*ln(e) = -5.878
\n" ); document.write( "the ln of e is 1 so we can just write
\n" ); document.write( "-.8t = -5.878
\n" ); document.write( "t = \"%28-5.878%29%2F%28-.8%29\"
\n" ); document.write( "t = 7.35 years to increase to 250000 fish
\n" ); document.write( ":
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\n" ); document.write( "did I explain well enough so you know what'sgoing on here? ankor@att.net\r
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