document.write( "Question 81194: Solve the following system by substitution
\n" ); document.write( "8x-4y=16
\n" ); document.write( "y=2x-4 \n" ); document.write( "

Algebra.Com's Answer #58200 by jainenderkapoor(61) $\"\"$ $\"About$

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8x-4y=16 ----(1)
\n" ); document.write( "y = 2x - 4 ----(2)\r
\n" ); document.write( "\n" ); document.write( "From the second equation
\n" ); document.write( "we have
\n" ); document.write( "y =2x - 4 ----- (3)\r
\n" ); document.write( "\n" ); document.write( "substituting this value in (1) equation, we get\r
\n" ); document.write( "\n" ); document.write( "8x - 3(2x - 4) = 16
\n" ); document.write( "8x - 6x + 12 = 16
\n" ); document.write( "2x + 12 = 16
\n" ); document.write( "2x + 12 - 12 = 16 - 12 (subtractinc 12 from both sides)
\n" ); document.write( "2x = 4
\n" ); document.write( "2x/2 = 4/2 (dividing both sides by 2)
\n" ); document.write( "x = 2\r
\n" ); document.write( "\n" ); document.write( "Putting this value of x in (3) equation we get\r
\n" ); document.write( "\n" ); document.write( "y = 2(2) - 4
\n" ); document.write( "y = 4 - 4
\n" ); document.write( "y = 0\r
\n" ); document.write( "\n" ); document.write( "so solution is x = 2 and y = 0\r
\n" ); document.write( "\n" ); document.write( "Hope the solution is clear to you. In case you have any other doubt, please contact me on jainenderkapoor@gmail.com I am available for Online Tutoring at very reasonable rates. \n" ); document.write( "

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