document.write( "Question 953020: Find the area of a circle in which a chord AB is 48 cm and the perpendicular bisector of the chord, originating at the centre of the circle, is 10 cm. \n" ); document.write( "

Algebra.Com's Answer #581986 by macston(5194) $\"\"$ $\"About$

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The perpendicular bisector and 1/2 of the chord are legs of a right triangle with the radius of the circle as hypotenuse, so:
\n" ); document.write( " $\"r%5E2=10cm%5E2%2B%28%281%2F2%2948cm%29%5E2\"$
\n" ); document.write( " $\"r%5E2=%28100cm%5E2%29%2B%2824cm%29%5E2\"$
\n" ); document.write( " $\"r%5E2=%28100cm%5E2%29%2B%28576cm%5E2%29\"$
\n" ); document.write( " $\"r%5E2=676cm%5E2\"$
\n" ); document.write( " $\"Area=pi%28r%5E2%29\"$ = $\"%28676cm%5E2%29pi\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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