document.write( "Question 81193: Solve the following system by substitution
\n" ); document.write( "5x-2y=-5
\n" ); document.write( "y-5x=3 \n" ); document.write( "
Algebra.Com's Answer #58198 by jainenderkapoor(61)\"\" \"About 
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5x-2y=-5 ----(1)
\n" ); document.write( "y-5x=3 ----(2)\r
\n" ); document.write( "\n" ); document.write( "From the second equation
\n" ); document.write( "we have
\n" ); document.write( "y - 5x = 3
\n" ); document.write( "y - 5x + 5x = 3 + 5x (adding 5x to both sides)
\n" ); document.write( "y = 3 + 5x ---- (3)\r
\n" ); document.write( "\n" ); document.write( "substituting this value in (1) equation, we get\r
\n" ); document.write( "\n" ); document.write( "5x - 2(3 + 5x) = -5
\n" ); document.write( "5x - 6 - 10x = -5
\n" ); document.write( "-5x - 6 = -5
\n" ); document.write( "-5x -6 + 6 = -5 +6 (adding 6 to both sides)
\n" ); document.write( "-5x = 1
\n" ); document.write( "-5x/-5 = 1/-5 (dividing both sides by -5)
\n" ); document.write( "x = -1/5\r
\n" ); document.write( "\n" ); document.write( "Putting this value of x in (3) equation we get\r
\n" ); document.write( "\n" ); document.write( "y = 3 + 5(-1/5)
\n" ); document.write( "y = 3 - 1
\n" ); document.write( "y = 2\r
\n" ); document.write( "\n" ); document.write( "so solution is x = -1/5 and y = 2\r
\n" ); document.write( "\n" ); document.write( "Hope the solution is clear to you. In case you have any other doubt, please contact me on jainenderkapoor@gmail.com I am available for Online Tutoring at very reasonable rates.
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