document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=81192>Question 81192</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jill has $3.50 in nickels and dimes.  If she has 50 coins, how many of each type of coin does she have?<BR>\n" );
document.write( "Nickels: ____<BR>\n" );
document.write( "Dimes:_____ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58195 by </B><A HREF=/tutors/aboutme.mpl?userid=sprolden><B>sprolden(40)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sprolden><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58195\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Jill has $3.50 in nickels and dimes.  If she has 50 coins, how many of each type of coin does she have?<BR>\n" );
document.write( "Nickels: ____<BR>\n" );
document.write( "Dimes:_____\r<BR>\n" );
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document.write( "1- You have to use trial and error on this problem. I'll start with 25 nickels and 25 dimes and continue from there until I get to $3.50.<BR>\n" );
document.write( "2- TRY: 25 nickels= 1.25  25 dimes= 2.50  total= $3.75 NOPE, this isn't it!!!!!!!!!!<BR>\n" );
document.write( "3- Try: 26 nickels= 1.30  24 dimes= 2.40 total= $3.70 NOPE!!!<BR>\n" );
document.write( "4- This time, I'll take away more than 1 coin from each. Try: 30 nickels= 1.50  20 dimes= 2.00 total= $3.00 YEP!!!!<BR>\n" );
document.write( "5- She has 30 nickels and 20 dimes.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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