document.write( "Question 952916: how many 5 digit counting numbers contain at least one 6
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Algebra.Com's Answer #581946 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "We can divide all the five digit numbers into two groups.\r
\n" ); document.write( "\n" ); document.write( "One group which contains all such numbers which do not have \"6\" at all, and the other group will be of such numbers which have at least one \"6\".
\n" ); document.write( "These two groups or sets are complementary to each other. They together make the set of all \"5+\"digit numbers.\r
\n" ); document.write( "\n" ); document.write( "It is easy to calculate the number of \"5\" digit numbers which do not contain \"6\" at all. If we calculate this number and subtract it from the total number of \"5\" digit numbers, we will get the required answer.\r
\n" ); document.write( "\n" ); document.write( "The total number of 5 digit numbers => \"99999+-+9999+=+90000\".\r
\n" ); document.write( "\n" ); document.write( "Out of these, the number of 5 digit numbers which do \"not\" contain \"6\" at all is equal to:
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\n" ); document.write( "\"9%2A9%2A9%2A9%2A9+=9%5E5=+59049\" (9 digits for each placeholder) \r
\n" ); document.write( "\n" ); document.write( "Therefore the number of five digit numbers which contain at least one \"6\" is:
\n" ); document.write( "\"90000+-59049+=+highlight%2830951%29\"\r
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