document.write( "Question 952938: complete the table for each function.
\n" ); document.write( "g(x)=-1/4sqrtx
\n" ); document.write( "x=0,1,4,9
\n" ); document.write( "--------
\n" ); document.write( "y-\r
\n" ); document.write( "\n" ); document.write( "not trying to type more than 1 question here, but the next one reads h(x)=sqrtx-2
\n" ); document.write( "The table is the same...I am really confused as to why change the g to an h? Do i have to change how to solve or what? confused. \r
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Algebra.Com's Answer #581939 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
complete the table for each function.
\n" ); document.write( "g(x)=-1/4sqrtx
\n" ); document.write( "x=0,1,4,9
\n" ); document.write( " --------
\n" ); document.write( "When x = 0, y = (-1/4)sqrt(0) = (-1/4)*0 = 0
\n" ); document.write( "When x = 1, y = (-1/4)sqrt(1) = (-1/4)*1 = -1/4
\n" ); document.write( "When x = 4, y = (-1/4)sqrt(4) = (-1/4)*2 = -1/2
\n" ); document.write( "When x = 9, y = (-1/4)*3 = -3/4
\n" ); document.write( "-----------------------------------------
\n" ); document.write( "The next one reads h(x)=sqrtx-2
\n" ); document.write( " The table is the same...I am really confused as to why change the g to an h? Do i have to change how to solve or what? confused.
\n" ); document.write( "They used h(x) instead of g(x) so you would know it was
\n" ); document.write( "a different function. It could have been k(x) or p(x) etc.
\n" ); document.write( "When x = 0, y = sqrt(0)-2 = 0-2 = -2
\n" ); document.write( "When x = 1, y = 1-2 = -1
\n" ); document.write( "When x = 4, y = 2-2 = 0
\n" ); document.write( "When x = 9, y = 3-2 = 1
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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