document.write( "Question 952900: Seriously stumped here, Please help me.
\n" ); document.write( "I have to describe and correct the error. \r
\n" ); document.write( "\n" ); document.write( "2b^2+b=6
\n" ); document.write( "b^2+1/2b=3
\n" ); document.write( "b^2+1/2b+(1/2)^2=3+(1/2)^2
\n" ); document.write( "(b+1/2)^2=3+1/4
\n" ); document.write( "b+1/2=+sqrt13/4
\n" ); document.write( "b=-1/2+sqrt13/2
\n" ); document.write( "b=-1+sqrt13dividedby 2 this is all the one problem..says to describe the error and correct it?
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Algebra.Com's Answer #581922 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
\"2b%5E2%2Bb=6\"
\n" ); document.write( "\"b%5E2%2B%281%2F2%29b=3\"
\n" ); document.write( "\"b%5E2%2B%281%2F2%29b%2B%281%2F2%29%5E2=3%2B%281%2F2%29%5E2\" Should add \"%281%2F4%29%5E2\" instead of \"%281%2F2%29%5E2\" here.
\n" ); document.write( "\"b%5E2%2B%281%2F2%29b%2B%281%2F4%29%5E2=3%2B%281%2F4%29%5E2\" This is what it should be.
\n" ); document.write( "\"%28b%2B1%2F4%29%5E2=3%2B1%2F16\" GIVEN:\"%28b%2B1%2F2%29%5E2\" would equal \"b%5E2%2B%28b%29%2B1%2F4\" and NOT \"b%5E2%2B%281%2F2%29b%2B%281%2F4%29\" The co=efficient of b would be 1, not 1/2.
\n" ); document.write( "\"b%2B1%2F4=sqrt%2849%2F16%29\"
\n" ); document.write( "\"b%2B1%2F4=7%2F4\"
\n" ); document.write( "\"b=6%2F4\"=\"1.5\"
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