document.write( "Question 81187: \"3%2F4x%2B2%2F5=+1\"\r
\n" ); document.write( "\n" ); document.write( "I tried common denominators to get:
\n" ); document.write( "12x/20x + 8x/20x = 20x
\n" ); document.write( "20x/20x=20x ?
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Algebra.Com's Answer #58192 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Paul did it one way, but I think the most efficient way\r\n" );
document.write( "is to clear of fractions:\r\n" );
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document.write( "\"3%2F%284x%29\" + \"2%2F5\" = \"1\"\r\n" );
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document.write( "Write the 1 as 1/1\r\n" );
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document.write( "\"3%2F%284x%29\" + \"2%2F5\" = \"1%2F1\"\r\n" );
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document.write( "Multiply every term by \"%28LCD%29%2F1\" which is \"%2820x%29%2F1\"\r\n" );
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document.write( "Write \"%2820x%29%2F1\"· in front of every term: \r\n" );
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document.write( "\"%2820x%29%2F1\"·\"3%2F%284x%29\" + \"%2820x%29%2F1\"·\"2%2F5\" = \"%2820x%29%2F1\"·\"1%2F1\"\r\n" );
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document.write( "In the first term cancel the 4x into the 20x and get 5.\r\n" );
document.write( "In the second term, cancel the 5 into the 20 and get 4:\r\n" );
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document.write( "\"5%2F1\"·\"3%2F1\" + \"%284x%29%2F1\"·\"2%2F1\" = \"%2820x%29%2F1\"·\"1%2F1\" \r\n" );
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document.write( "or\r\n" );
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document.write( "\"15%2F1\" + \"%288x%29%2F1\" = \"%2820x%29%2F1\"\r\n" );
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document.write( " Erase the 1's on the bottoms:\r\n" );
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document.write( "\"15\" + \"8x\" = \"20x\"\r\n" );
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document.write( "Subtract \"8x\" from both sides, getting \"15\" on the left\r\n" );
document.write( "and \"12x\" on the right\r\n" );
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document.write( "          \"15\" = \"12x\"\r\n" );
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document.write( "Divide both sides by \"12\"\r\n" );
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document.write( "           \"15%2F12\" = \"%2812x%29%2F12\"\r\n" );
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document.write( "Reduce fraction:\r\n" );
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document.write( "             \"5%2F4\" = \"x\"\r\n" );
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document.write( "Edwin

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