document.write( "Question 952747: All applicants for a job in X-Company should take a test. To be invited for an interview your score on the test should be on the top 10% percent of all applicants. Results of the test have Normal Distribution with the mean 340 and Standard Deviation 85. Take values 340, 85 and 10% assigned for you in the table below and find, what should be your score on the test (higher than what value ?) to be invited for the interview. \r
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document.write( "Take values 340, 85 and 10%. From Appendix Table for Normal Distribution find z-value that has area to the left close to
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document.write( " 1-10% (10% should be in decimal form).
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document.write( " 2. In formula z=(x-340)/85 to plug your z, 340 and 85 and solve for x.
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document.write( "That will be score on the test required to be invited for the interview.
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Algebra.Com's Answer #581910 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! All applicants for a job in X-Company should take a test. To be invited for an interview your score on the test should be on the top 10% percent of all applicants. Results of the test have Normal Distribution with the mean 340 and Standard Deviation 85. Take values 340, 85 and 10% assigned for you in the table below and find, what should be your score on the test (higher than what value ?) to be invited for the interview. \n" ); document.write( "---- \n" ); document.write( "I used a TI-84+ calculator. \n" ); document.write( "Find the z-value with a left tail of 0.90:: invNorm(0.9) = 1.2816 \n" ); document.write( "Find the corresponding score using:: x = z*s+u \n" ); document.write( "x = 1.2816*85+340 \n" ); document.write( "x = 448.93 \n" ); document.write( "---- \n" ); document.write( "Ans: Minimum score to be invited:: 449 \n" ); document.write( "----- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "-------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |