document.write( "Question 81175This question is from textbook
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document.write( ": insert two geometric means between 6 and 162 \n" );
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Algebra.Com's Answer #58187 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! insert two geometric means between 6 and 162 \n" ); document.write( "--------- \n" ); document.write( "Let x and y be the two geometric means: \n" ); document.write( "--------- \n" ); document.write( "EQUATION: \n" ); document.write( "6/x = x/y = y/162 \n" ); document.write( "Then you have two equation: \n" ); document.write( "6y=x^2 and y^2=162x \n" ); document.write( "Solve the 1st for y: y=x^2/6 \n" ); document.write( "Substitute into the 2nd to get: \n" ); document.write( "(x^2/6)^2=162x \n" ); document.write( "x^4 = 6^2*162x \n" ); document.write( "x^4-36*162x=0 \n" ); document.write( "Factor: \n" ); document.write( "x(x^3-5832)=0 \n" ); document.write( "x^3=5832 \n" ); document.write( "x=18 \n" ); document.write( "------- \n" ); document.write( "Substitute that into y^2=162x to solve for y \n" ); document.write( "y^2=162*18 \n" ); document.write( "y=54 \n" ); document.write( "--------- \n" ); document.write( "Then 6/18=18/54=54/162 \n" ); document.write( "18 and 54 are the two geometric means \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |