document.write( "Question 952802: How many years, correct to the nearest tenth of a year, will it take for a sum of money to double if it's invested at 9.5%, compounded quarterly? \n" ); document.write( "
Algebra.Com's Answer #581847 by stanbon(75887)\"\" \"About 
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How many years, correct to the nearest tenth of a year, will it take for a sum of money to double if it's invested at 9.5%, compounded quarterly?
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\n" ); document.write( "A(t) = P(1+(r/n))^(nt)
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\n" ); document.write( "Comment::
\n" ); document.write( "Notice that (1+(r/n))^(nt) is the multiplier.
\n" ); document.write( "When that multiplier equal \"2\" your money has doubled.\r
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\n" ); document.write( "Solve::
\n" ); document.write( "(1 + (0.095/4))^(4t) = 2
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\n" ); document.write( "(1.02375)^(4t) = 2
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\n" ); document.write( "Since the variable is in the exponent, take the log to get:
\n" ); document.write( "(4t)*log (1.02375) = log(2)
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\n" ); document.write( "4t = log(2)/log(1.02375) = 29.53
\n" ); document.write( "time = 29.53/4 = 7.38 years
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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