document.write( "Question 952608: Can you please help me with this word problem: A train leaves New York for Boston, 200 miles away, at 5:00 P.M. and averages 40 mph. Another train leaves Boston for New York on an adjacent set of tracks at 3:00 P.M. and averages 45 mph. At what time will the trains meet? (Round to the nearest minute.) \n" ); document.write( "
Algebra.Com's Answer #581770 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A train leaves New York for Boston, 200 miles away, at 5:00 P.M. and averages 40 mph. \n" ); document.write( " Another train leaves Boston for New York on an adjacent set of tracks at 3:00 P.M. and averages 45 mph. \n" ); document.write( " At what time will the trains meet? \n" ); document.write( ": \n" ); document.write( "Find how many hrs from 3Pm until the meet \n" ); document.write( ": \n" ); document.write( "let t = travel time of the Bos/NY train (leaves at 3:00) \n" ); document.write( "then \n" ); document.write( "(t-2) = travel time of the NY/Bos train (leaves at 5:00) \n" ); document.write( ": \n" ); document.write( "We know when they will meet the sum of their distances = 200 mi \n" ); document.write( "write a distance equation using this fact; dist = speed * time \n" ); document.write( "40(t-2) + 45t = 200 mi \n" ); document.write( "40t - 80 + 45t = 200 \n" ); document.write( "40t + 45t = 200 + 80 \n" ); document.write( "85t = 280 \n" ); document.write( "t = 280/85 \n" ); document.write( "t = 3.294 hrs, which is 3 + .294(60) = 3 hrs 18 min \n" ); document.write( "then \n" ); document.write( "the trains will meet: 3:00 + 3:18 = 6:18 \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "Confirm this solution by finding actual dist each train traveled \n" ); document.write( "3.294 * 45 = 148.23 mi \n" ); document.write( "1.294 * 40 = 51.76 mi (left 2hr later) \n" ); document.write( "------------------------ \n" ); document.write( "total distance: 199 mi, close enough \n" ); document.write( " |