document.write( "Question 952435: find the dimensions of an open box whose base is a rectangle whose length is twice its width. if its volume is 176 cubic feet and the totals surface area is 164 square feet
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Algebra.Com's Answer #581716 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Find the dimensions of an open box whose base is a rectangle whose length is twice its width. \n" ); document.write( " if its volume is 176 cubic feet and the totals surface area is 164 square feet \n" ); document.write( ": \n" ); document.write( "Vol: L * W * h = 176 \n" ); document.write( "and \n" ); document.write( "S.A.: (L*W) + 2(L*h) + 2(W*h) = 164 \n" ); document.write( ": \n" ); document.write( "\"length is twice its width.\" \n" ); document.write( "L = 2W \n" ); document.write( "Replace L with 2W \n" ); document.write( "Vol: 2W * W * h = 176 \n" ); document.write( "2W^2*h = 176 \n" ); document.write( "Simplif, divide by 2 \n" ); document.write( "W^2h = 88 \n" ); document.write( "h = \n" ); document.write( ": \n" ); document.write( "S.A.: 2W^2 + 2(2W*h) + 2(W*h) = 164 \n" ); document.write( "Simplify,divide by 2 \n" ); document.write( " W^2 + 2Wh + Wh = 82 \n" ); document.write( " W^2 + 3Wh = 82 \n" ); document.write( "replace h with \n" ); document.write( "W^2 + 3W( \n" ); document.write( "W^2 + \n" ); document.write( ": \n" ); document.write( "Plot this equation \n" ); document.write( " \n" ); document.write( "Using the integer solution: w = 4 ft is the width \n" ); document.write( "then 2(4) = 8 ft is the length \n" ); document.write( "Find the height \n" ); document.write( "h = \n" ); document.write( "h = 5.5 ft is the height \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this, find the surface area with these dimensions \n" ); document.write( "(8*4) + 2(8*5.5) + 2(4*5.5) = \n" ); document.write( "32 + 88 + 44 = 164 \n" ); document.write( " \n" ); document.write( " |