document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=952517>Question 952517</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has two solutions of H2SO4. One has a 40% concentration and the other has a 25% concentration. How many liters of each solution must be mixed to obtain 125 liters of 31% solution?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #581714 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=581714\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist has two solutions of H2SO4. One has a 40% concentration and the other has a 25% concentration. How many liters of each solution must be mixed to obtain 125 liters of 31% solution? <BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.40x + 0.25(125-x) = 0.31*125<BR>\n" );
document.write( "40x + 25*125 - 25x = 31*125<BR>\n" );
document.write( "15x = 6*125<BR>\n" );
document.write( "x = 50 liters (amt of 40% solution needed)<BR>\n" );
document.write( "125-x = 75 liters (amt. of 25% colution needed)<BR>\n" );
document.write( "----------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "--------- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );