document.write( "Question 952495: Susan is twice as old as Mary. In five years, their ages will total 49. How old is each today? \n" ); document.write( "
Algebra.Com's Answer #581685 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Susan is twice as old as Mary. In five years, their ages will total 49. How old is each today? \n" ); document.write( "------------ \n" ); document.write( "Equation: \n" ); document.write( "s = 2m \n" ); document.write( "s+5 + m+5 = 49 \n" ); document.write( "------ \n" ); document.write( "s = 2m \n" ); document.write( "s + m = 39 \n" ); document.write( "---------------- \n" ); document.write( "Substitute for \"s\" and solve for \"m\":: \n" ); document.write( "2m + m = 39 \n" ); document.write( "3m = 39 \n" ); document.write( "m = 13 yrs (Mary's age now) \n" ); document.write( "-------------- \n" ); document.write( "Solve for \"s\":: \n" ); document.write( "s = 2m \n" ); document.write( "s = 2(13) \n" ); document.write( "s = 26 yrs (Susan's age now) \n" ); document.write( "-------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "-------------- \n" ); document.write( " |