document.write( "Question 952495: Susan is twice as old as Mary. In five years, their ages will total 49. How old is each today? \n" ); document.write( "
Algebra.Com's Answer #581685 by stanbon(75887)\"\" \"About 
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Susan is twice as old as Mary. In five years, their ages will total 49. How old is each today?
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\n" ); document.write( "Equation:
\n" ); document.write( "s = 2m
\n" ); document.write( "s+5 + m+5 = 49
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\n" ); document.write( "s = 2m
\n" ); document.write( "s + m = 39
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\n" ); document.write( "Substitute for \"s\" and solve for \"m\"::
\n" ); document.write( "2m + m = 39
\n" ); document.write( "3m = 39
\n" ); document.write( "m = 13 yrs (Mary's age now)
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\n" ); document.write( "Solve for \"s\"::
\n" ); document.write( "s = 2m
\n" ); document.write( "s = 2(13)
\n" ); document.write( "s = 26 yrs (Susan's age now)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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