document.write( "Question 952472: Find four consecutive even integers such that twice the sum of the second and third exceeds 3 times the first by 32. \n" ); document.write( "
Algebra.Com's Answer #581684 by macston(5194)\"\" \"About 
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first=x; second=x+2; third=x+4; fourth=x+6
\n" ); document.write( "2((x+2)+(x+4))=3(x)+32
\n" ); document.write( "2(2x+6)=3x+32
\n" ); document.write( "4x+12=3x+32
\n" ); document.write( "x=20 ANSWER 1: The first integer is 20.
\n" ); document.write( "x+2=22 ANSWER 2: The second integer is 22.
\n" ); document.write( "x+4=24 ANSWER 3: The third integer is 24.
\n" ); document.write( "x+6=26 ANSWER 4: The fourth integer is 26.
\n" ); document.write( "CHECK:
\n" ); document.write( "2(22+24)=3(20)+32
\n" ); document.write( "2(46)=60+32
\n" ); document.write( "92=92\r
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