document.write( "Question 952486: Please help me solve this equation: \"+%28a-2%29%2Ax%5E2=0+\" a≠2 ; result= double 0
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Algebra.Com's Answer #581679 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"+%28a-2%29%2Ax%5E2=0+\" \r
\n" ); document.write( "\n" ); document.write( "\"a%3C%3E2\" ; result= double 0\r
\n" ); document.write( "\n" ); document.write( "you will get result= double 0 for any value of \"a+\" you choose because \"%28a-2%29\" is actually coefficient in front of variable \"x\"\r
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\n" ); document.write( "\n" ); document.write( "example:\r
\n" ); document.write( "\n" ); document.write( "\"+%28a-2%29%2Ax%5E2=0+\" if \"a=-5\"\r
\n" ); document.write( "\n" ); document.write( "\"+%28-5-2%29%2Ax%5E2=0+\" \r
\n" ); document.write( "\n" ); document.write( "\"+-7x%5E2=0+\" \r
\n" ); document.write( "\n" ); document.write( "solution: result= double 0\r
\n" ); document.write( "\n" ); document.write( "\"+%28a-2%29%2Ax%5E2=0+\" if \"a=5\"\r
\n" ); document.write( "\n" ); document.write( "\"+%285-2%29%2Ax%5E2=0+\" \r
\n" ); document.write( "\n" ); document.write( "\"+3x%5E2=0+\" \r
\n" ); document.write( "\n" ); document.write( "solution: result= double 0\r
\n" ); document.write( "\n" ); document.write( "recall discriminant \"b%5E2-4ac\":\r
\n" ); document.write( "\n" ); document.write( "the rule: if \"b%5E2-4ac=0\", there will be 1 double 0, or one real root\r
\n" ); document.write( "\n" ); document.write( "in your case \"+%28a-2%29%2Ax%5E2=0+\"\r
\n" ); document.write( "\n" ); document.write( "the value for \"a\" is actually \"a-2\",\"b=0\", and \"c=0\"\r
\n" ); document.write( "\n" ); document.write( "\"0%5E2-4%28a-2%29%2A0=0\"\r
\n" ); document.write( "\n" ); document.write( "\"0-4%28a-2%29%2A0=0\"=> no matter what you put for \"a\" you will get\r
\n" ); document.write( "\n" ); document.write( "\"0=0\"\r
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