document.write( "Question 952453: IN A RIGHT TRIANGLE, THE HYPOTENUSE IS 1 FOOT MORE THAN THE LONG LEG, WHILE THE SHORT LEG IS 11FT. LESS THAN HALF THE LONG LEG. YOUR GOAL IS TO FIND THE PERIMETER OF THIS TRIANGLE. \n" ); document.write( "
Algebra.Com's Answer #581655 by macston(5194)\"\" \"About 
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b=long leg; a=short leg=(0.5b)-11ft; c=hypotenuse=b+1
\n" ); document.write( "\"a%5E2%2Bb%5E2=c%5E2\" Substitute for a and c, solve for b
\n" ); document.write( "\".25b%5E2-11b%2B121%2Bb%5E2=b%5E2%2B2b%2B1\"
\n" ); document.write( "\"1.25b%5E2-11b%2B121=b%5E2%2B2b%2B1\"Subtract\"%28b%5E2%2B2b%2B1%29\" from each side.
\n" ); document.write( "\"0.25b%5E2-13b%2B120=0\"\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ab%5E2%2Bbb%2Bc=0\" (in our case \"0.25b%5E2%2B-13b%2B120+=+0\") has the following solutons:
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\n" ); document.write( " \"b%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-13%29%5E2-4%2A0.25%2A120=49\".
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\n" ); document.write( " Discriminant d=49 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--13%2B-sqrt%28+49+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"b%5B1%5D+=+%28-%28-13%29%2Bsqrt%28+49+%29%29%2F2%5C0.25+=+40\"
\n" ); document.write( " \"b%5B2%5D+=+%28-%28-13%29-sqrt%28+49+%29%29%2F2%5C0.25+=+12\"
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\n" ); document.write( " Quadratic expression \"0.25b%5E2%2B-13b%2B120\" can be factored:
\n" ); document.write( " \"0.25b%5E2%2B-13b%2B120+=+0.25%28b-40%29%2A%28b-12%29\"
\n" ); document.write( " Again, the answer is: 40, 12.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+0.25%2Ax%5E2%2B-13%2Ax%2B120+%29\"

\n" ); document.write( "\n" ); document.write( "b=40 or b=12 (long leg)
\n" ); document.write( "For b=40:
\n" ); document.write( "a=0.5b-11ft=0.5(40)-11 ft=9 ft (short leg)
\n" ); document.write( "c=b+1=40ft+1 ft=41 ft(hypotenuse)
\n" ); document.write( "For b=12
\n" ); document.write( "a=.5(12)-11 ft=6-11=-5ft does not work
\n" ); document.write( "ANSWER 1: The long leg is 40 feet.
\n" ); document.write( "ANSWER 2: The short leg is 9 feet.
\n" ); document.write( "ANSWER 3: The hypotenuse is 41 feet.
\n" ); document.write( "CHECK:
\n" ); document.write( "\"a%5E2%2Bb%5E2=c%5E2\"
\n" ); document.write( "\"%289+ft%29%5E2%2B%2840+ft%29%5E2=%2841+ft%29%5E2\"
\n" ); document.write( "\"81ft%5E2%2B1600ft%5E2=1681ft%5E2\"
\n" ); document.write( "\"1681ft%5E2=1681ft%5E2\"
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