document.write( "Question 952453: IN A RIGHT TRIANGLE, THE HYPOTENUSE IS 1 FOOT MORE THAN THE LONG LEG, WHILE THE SHORT LEG IS 11FT. LESS THAN HALF THE LONG LEG. YOUR GOAL IS TO FIND THE PERIMETER OF THIS TRIANGLE. \n" ); document.write( "
Algebra.Com's Answer #581655 by macston(5194)![]() ![]() You can put this solution on YOUR website! b=long leg; a=short leg=(0.5b)-11ft; c=hypotenuse=b+1 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "b=40 or b=12 (long leg) \n" ); document.write( "For b=40: \n" ); document.write( "a=0.5b-11ft=0.5(40)-11 ft=9 ft (short leg) \n" ); document.write( "c=b+1=40ft+1 ft=41 ft(hypotenuse) \n" ); document.write( "For b=12 \n" ); document.write( "a=.5(12)-11 ft=6-11=-5ft does not work \n" ); document.write( "ANSWER 1: The long leg is 40 feet. \n" ); document.write( "ANSWER 2: The short leg is 9 feet. \n" ); document.write( "ANSWER 3: The hypotenuse is 41 feet. \n" ); document.write( "CHECK: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |