document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=952385>Question 952385</A>: <I><SPAN STYLE=\"word-break: break-all;\"> venus and serena measured a tennis court and found that it was 42 feet longer than it was wide and had a perimeter of 228 feet. what were the length and the width of the tennis court. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #581619 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=581619\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=width; L=length=W+42 feet; P=perimeter=2(L+W)=228 ft<BR>\n" );
document.write( "228 ft=2(L+W) Divide each side by 2.<BR>\n" );
document.write( "114 ft=L+W substitute for L<BR>\n" );
document.write( "114 ft=W+42ft+W Subtract 42ft from each side. <BR>\n" );
document.write( "72 ft=2W Divide each side by 2.<BR>\n" );
document.write( "36 ft=W ANSWER 1: The width is 36 feet.<BR>\n" );
document.write( "L=W+42 ft=36 ft+42 ft=78 ft ANSWER 2: The length is 78 feet<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "228ft=2(78ft+36ft)<BR>\n" );
document.write( "228ft=2(114ft)<BR>\n" );
document.write( "228ft=228ft </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );