document.write( "Question 952378: Stacey is selling tickets to the school play. The tickets are $8 for adults and $3 for children. She sells twice as many adult tickets as children's tickets and brings in a total of $380. How many of each kind of ticket did she sell? \n" ); document.write( "
Algebra.Com's Answer #581600 by macston(5194)![]() ![]() You can put this solution on YOUR website! A=adult tickets=2C; C=child tickets \n" ); document.write( "$8A+$3C=$380 Substitute for A \n" ); document.write( "$8(2C)+$3C=$380 \n" ); document.write( "$16C+$3C=$380 \n" ); document.write( "$19C=$380 Divide each side by $19 \n" ); document.write( "C=20 ANSWER 1: She sold 20 Child tickets. \n" ); document.write( "A=2C=2(20)=40 ANSWER 2: She sold 40 Adult tickets. \n" ); document.write( "CHECK: \n" ); document.write( "$8A+$3C=$380 \n" ); document.write( "$8(40)+$3(20)=$380 \n" ); document.write( "$320+$60=$380 \n" ); document.write( "$380=$380\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |