document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=952361>Question 952361</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A restaurant with 23 employees.  The number of waiters is twice the number of managers and there are three more chefs than managers.  Find the number of waiters, managers and chefs. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #581595 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=581595\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> waiters :w<BR>\n" );
document.write( "managers: m<BR>\n" );
document.write( "chefs: c\r<BR>\n" );
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document.write( "w+m+c = 23, and w = 2m, and c = m+3 So we can rewrite our initial equation, substituting like this:\r<BR>\n" );
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document.write( "m + 2m + m + 3 = 23 add m's on left and subtract 3 on both sides:<BR>\n" );
document.write( "4m = 20<BR>\n" );
document.write( "m =  20/4 = 5<BR>\n" );
document.write( "So, we have:<BR>\n" );
document.write( "m = 5 managers<BR>\n" );
document.write( "2m = 2(5) = 10 waiters<BR>\n" );
document.write( "m + 3 = 5 + 3 = 8 chefs<BR>\n" );
document.write( "Proof: 5 + 10 + 8 = 23 We've got the right answer.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );