document.write( "Question 952302: Premise: ~(A->(B&C))\r
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document.write( "Conclusion: ~(A<->(B&C))\r
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document.write( "I've tried to Provisionally assume A<->(B&C), but I don't understand double arrow rules that well. \n" );
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Algebra.Com's Answer #581570 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Hint: \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A<->(B&C) breaks down into [A -> (B&C)] & [(B&C) -> A] using the material equivalence rule.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "material equivalence rule: P <--> Q turns into [P -> Q] & [Q -> P]\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------------------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you need more one-on-one help, email me at jim_thompson5910@hotmail.com. You can ask me a few more questions for free, but afterwards, I would charge you ($2 a problem to have steps shown or $1 a problem for answer only).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Alternatively, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Any amount is greatly appreciated as it helps me a lot. This donation is to support free tutoring. Thank you.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jim\r \n" ); document.write( "\n" ); document.write( "------------------------------------------------------------------------------------------------------------------------ \n" ); document.write( " |