document.write( "Question 952302: Premise: ~(A->(B&C))\r
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\n" ); document.write( "\n" ); document.write( "I've tried to Provisionally assume A<->(B&C), but I don't understand double arrow rules that well.
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Algebra.Com's Answer #581570 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Hint: \r
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\n" ); document.write( "\n" ); document.write( "A<->(B&C) breaks down into [A -> (B&C)] & [(B&C) -> A] using the material equivalence rule.\r
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\n" ); document.write( "\n" ); document.write( "material equivalence rule: P <--> Q turns into [P -> Q] & [Q -> P]\r
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\n" ); document.write( "\n" ); document.write( "If you need more one-on-one help, email me at jim_thompson5910@hotmail.com. You can ask me a few more questions for free, but afterwards, I would charge you ($2 a problem to have steps shown or $1 a problem for answer only).\r
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\n" ); document.write( "\n" ); document.write( "Jim\r
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