document.write( "Question 952121: In an examination Mr. X got a third of the answers wrong. In the same examination Mr. Y got 5 of them wrong. Between both of them they answered three quarters of the questions right. How many questions did Mr. X answer correctly? \n" ); document.write( "
Algebra.Com's Answer #581559 by Edwin McCravy(20065) You can put this solution on YOUR website! In an examination Mr. X got a third of the answers wrong. In the same \n" ); document.write( "examination Mr. Y got 5 of them wrong. Between both of them they answered \n" ); document.write( "three quarters of the questions right. How many questions did Mr. X answer \n" ); document.write( "correctly? \n" ); document.write( " The number of questions is a multiple of 3\r\n" ); document.write( "because Mr X got 1/3 of them wrong.\r\n" ); document.write( "\r\n" ); document.write( "The number of questions is also a multiple\r\n" ); document.write( "of 4 because together they got 3/4 of them\r\n" ); document.write( "right. \r\n" ); document.write( "\r\n" ); document.write( "Therefore the number of questions is a\r\n" ); document.write( "multiple of 12, say 12k, where k is a\r\n" ); document.write( "positive integer.\r\n" ); document.write( "\r\n" ); document.write( "We use the \"sieve\" formula: \r\n" ); document.write( "\r\n" ); document.write( "N(A or B) = N(A) + N(B) - N(A and B)\r\n" ); document.write( "\r\n" ); document.write( "A = set of questions that Mr X got right\r\n" ); document.write( "B = set of questions that Mr Y got right\r\n" ); document.write( "\r\n" ); document.write( "Since Mr X missed 1/3 of the 12k, he got \r\n" ); document.write( "2/3 of 12k right.\r\n" ); document.write( "Since Mr Y missed 5 of the 12k, he got\r\n" ); document.write( "12k-5 right\r\n" ); document.write( "Since together they got 3/4 right, together\r\n" ); document.write( "they got 3/4 of 12k right.\r\n" ); document.write( "\r\n" ); document.write( "N(A) =\n" ); document.write( " |