document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=952227>Question 952227</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A first number plus twice a second number is 13. Twice the first number plus the second totals 8. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #581530 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=581530\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F=first number; S=second number<BR>\n" );
document.write( "F+2S=13<BR>\n" );
document.write( "F=13-2S<BR>\n" );
document.write( "2F+S=8 Substitute for F<BR>\n" );
document.write( "2(13-2S)+S=8<BR>\n" );
document.write( "26-4S+S=8<BR>\n" );
document.write( "26-3S=8 Add 3S to each side.<BR>\n" );
document.write( "26=3S+8 Subtract 8 from each side.<BR>\n" );
document.write( "18=3S Divide each side by 3.<BR>\n" );
document.write( "6=S ANSWER 1: The second number is 6. <BR>\n" );
document.write( "F=13-2S=13-12=1 ANSWER 2: The first number is 1.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "F+2S=13<BR>\n" );
document.write( "1+2(6)=13<BR>\n" );
document.write( "1+12=13<BR>\n" );
document.write( "13=13<BR>\n" );
document.write( "2F+S=8<BR>\n" );
document.write( "2(1)+6=8<BR>\n" );
document.write( "2+6=8<BR>\n" );
document.write( "8=8 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );