document.write( "Question 952059: A river is flowing downstream at a rate of 2 metres per second. Brendan, who has an average swimming speed of 3 metres per second, decides to go for a swim in the river. He dives into the river and swims downstream to a certain point then swims back upstream to the starting point. The total time taken is 4 minutes. How far did Brendan swim downstream?\r
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Algebra.Com's Answer #581448 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The current, \"+c+=+2+\" m/sec
\n" ); document.write( "Swimming speed is \"+s+=+3+\" m/sec
\n" ); document.write( "\"+3+%2B+2+=+5+\" m/sec downstream
\n" ); document.write( "\"+3+-+2+=+1+\" m/sec upstream
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\n" ); document.write( "Let \"+d+\" = one-way distance he swims
\n" ); document.write( "Let \"+t+\" = his time in minutes to go downstream
\n" ); document.write( "Convert \"+4+\" min to sec
\n" ); document.write( "\"+4%2A60+=+240+\" sec
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\n" ); document.write( "Equation for downstream:
\n" ); document.write( "(1) \"+d+=+5%2At+\"
\n" ); document.write( "Equation for upstream:
\n" ); document.write( "(2) \"+d+=+1%2A%28+240+-+t+%29+\"
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\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+5t+=+240+-+t+\"
\n" ); document.write( "(2) \"+6t+=+240+\"
\n" ); document.write( "(2) \"+t+=+40+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+d+=+5%2At+\"
\n" ); document.write( "(1) \"+d+=+5%2A40+\"
\n" ); document.write( "(1) \"+d+=+200+\"
\n" ); document.write( "He swam 200 m
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\n" ); document.write( "check:
\n" ); document.write( "(2) \"+d+=+1%2A%28+240+-+t+%29+\"
\n" ); document.write( "(2) \"+200+=+1%2A%28+240+-+40+%29+\"
\n" ); document.write( "(2) \"+200+=+200+\"
\n" ); document.write( "OK
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