document.write( "Question 951981: You invest $14000, part of it in stock that paid 15% annual interest. However, the rest of the money suffered 5% loss. If the total annual income from both investments was $700, how much was invested at each rate?
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Algebra.Com's Answer #581442 by macston(5194)\"\" \"About 
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F=amount at 15%; L=amount at loss
\n" ); document.write( "F+L=$14000
\n" ); document.write( "F=$14000-L
\n" ); document.write( "0.15F-0.05L=$700 Substitute for F and solve for L
\n" ); document.write( "0.15($14000-L)-0.05L=$700
\n" ); document.write( "$2100-0.15L-0.05L=$700 Subtract $700 from each side.
\n" ); document.write( "$1400-0.20L=0 Add 0.20L to each side
\n" ); document.write( "$1400=0.20L Divide each side by 0.02
\n" ); document.write( "$7000=L ANSWER 1: $7000 suffered a 5% loss.
\n" ); document.write( "F=$14000-L=$14000-$7000=$7000 ANSWER 2: $7000 was invested at 15%
\n" ); document.write( "CHECK:
\n" ); document.write( "0.15($7000)-0.05($7000)=$700
\n" ); document.write( "$1050-$350=$700
\n" ); document.write( "$700=$700
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