document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=952042>Question 952042</A>: <I><SPAN STYLE=\"word-break: break-all;\"> when asked how many pennies she had, a collector said: <BR>\n" );
document.write( "If I arrange them in attacks of 5, none are left over. <BR>\n" );
document.write( " If I arrange then in stacks of 6, none are left over. <BR>\n" );
document.write( " If I arrange them in stacks of 7, one is left over.  <BR>\n" );
document.write( "what is the least number of coins she could have? explain your answer </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #581429 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=581429\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since we're looking for least, let's start at the beginning.<BR>\n" );
document.write( "We know that it will be a multiple of 5 and 6.  5*6=30, so a multiple of 30.<BR>\n" );
document.write( "30,60,90,120,150,180,210<BR>\n" );
document.write( "Does 7 go into any of those with 1 remainder?<BR>\n" );
document.write( "30/7 = 4 r 2<BR>\n" );
document.write( "60/7 = 9 r 4<BR>\n" );
document.write( "90/7 = 12 r 6 <BR>\n" );
document.write( "<b>120/7 = 17 r 1</b> </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );