document.write( "Question 951987: Use natural logarithms to solve for x in terms of y.
\n" ); document.write( "y = (e^x + e^−x)/(e^x − e^−x)\r
\n" ); document.write( "\n" ); document.write( "I'm ending up with x=ln(1+y)/(y-1) but that is incorrect.
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Algebra.Com's Answer #581379 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
\"y=%28e%5Ex%2Be%5E%28-x%29%29%2F%28e%5Ex-e%5E%28-x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28%28e%5Ex%2Be%5E%28-x%29%29%2F%28e%5Ex-e%5E%28-x%29%29%29%28e%5Ex%2Fe%5Ex%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28e%5E%282x%29%2B1%29%2F%28e%5E%282x%29-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%28e%5E%282x%29-1%29=e%5E%282x%29%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "Steps up to that should make sense, and you can finish to obtain a different result than before.
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