document.write( "Question 951943: A rectangle has a perimeter of 86 and an area of 252. Its length is 8 more than 4 times its width. Write and solve a system of equations to find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #581376 by addingup(3677)\"\" \"About 
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Let's call the width w and the length l.\r
\n" ); document.write( "\n" ); document.write( "The perimeter is 86 and the area 252.
\n" ); document.write( "And the problem states that the length is 4w+8.\r
\n" ); document.write( "\n" ); document.write( "Perimeter: 2w + 2l = 86
\n" ); document.write( "Area : w x l = 252\r
\n" ); document.write( "\n" ); document.write( "Now let's solve one at the time. Since we know that l = 4w+8, let's substitute:
\n" ); document.write( "2w + 2(4w+8) = 86 Multiply on left:
\n" ); document.write( "2w + 8w + 16 = 86 Add on left and subtract 16, both sides:
\n" ); document.write( "10w = 70 Divide by 10, both sides:
\n" ); document.write( "w = 7
\n" ); document.write( "The width is: 7 and the length 4(7) + 8 = 36
\n" ); document.write( "Let’s see:
\n" ); document.write( "2w + 2l = 86
\n" ); document.write( "2(7) + 2(4(7)+8) = 86 (remember the order of operations 1)multiply inside, 2) clear parentheses, etc.)
\n" ); document.write( "14 + 72 = 86
\n" ); document.write( "86 = 86 We’ve got the correct answer.
\n" ); document.write( "Now the area:
\n" ); document.write( "w x l = 252
\n" ); document.write( "7 x 36 = 252
\n" ); document.write( "252 = 252 Again, we’ve got the right answer.
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