document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=951875>Question 951875</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi!! I am learning the substitution method with systems of equations and the elimination method!! how do I start solving this problem? 'Four times the larger of two numbers is equal to seven times the smaller. The sum of the numbers is 22. Find the numbers.' \r<BR>\n" );
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document.write( "thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #581319 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=581319\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here's a good way to start:\r<BR>\n" );
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document.write( "Let x= larger number<BR>\n" );
document.write( "And let y= smaller. umber<BR>\n" );
document.write( "Now we are told that:<BR>\n" );
document.write( "4x=7y--------eq1<BR>\n" );
document.write( "We are also told that:<BR>\n" );
document.write( "x+y=22-----eq2<BR>\n" );
document.write( "Substitution method looks easier.<BR>\n" );
document.write( "From eq1 x=(7/4)y. Substitute this into eq2<BR>\n" );
document.write( "(7 /4)y +y=22<BR>\n" );
document.write( "(7/4)y+(4/4)y=22<BR>\n" );
document.write( "(11/4)y=22 multiply each side by 4<BR>\n" );
document.write( "11y=88<BR>\n" );
document.write( "y=8<BR>\n" );
document.write( "From eq2, x+8=22<BR>\n" );
document.write( "x=14<BR>\n" );
document.write( "Hope this helps ---ptaylor </SPAN>\n" );
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